PHP code to call image

I'm trying to call a jpg image that is in a directory above my html dir. How can I get that jpg file and use it in an img tag?

Jimmy

Wish I had an answer for you, but I tossed the thread to Develish who may have a clue how to structure the tag you need.

I know on Windows, that if I am calling a file above my root - I need to use an absolute URL, like d:\domains\coreybryant.org\wwwroot\default.asp and the image would be in the folder d:\domains\coreybryant.org\secureimages\filename.j pg

Also the IUSR needs to have access as well (I think). I don't know if that us a start until someone comes in with PHP knowledge. Sorry I mainly do ASP and rely on the programmers for most of that

I'd use a script reading out the image and displaying it - I try to dig one out

Dunno if it may be done otherwise - chilihost is more webserver savy than I - i try to write my own tools :D

Thanks for the replies. I was able to use a script to pull and display the image.

Jimmy

oh darn

I was to slow - gimme a gun to my head - but for the others:

heres a way to do it

PHP Code:

---

<?php

$imgpath = '/path/to/images/'; //webserver user needs read access to this folder

if ($imgname != "")
{
   $im = @imagecreatefromjpeg($imgpath.$imgname); /* Attempt to open */
   if (!$im) { /* See if it failed */
       // if the call of the image failed create a nice little image with the error message
       $im  = imagecreatetruecolor(150, 30); /* Create a black image */
       $bgc = imagecolorallocate($im, 255, 255, 255);
       $tc  = imagecolorallocate($im, 0, 0, 0);
       imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
       /* Output an errmsg */
       imagestring($im, 1, 5, 5, "Error loading $imgname", $tc);
   }
   imagejpeg($im);
}


?>

---

Untested but it should do the work

Just in case - I totally forgot about Calling files outside of the public_html on server as well. The other solution might be a solution as well but not knowing PHP I thought that thread could help

Why not just use html? Im obviously missing something? like or use the full web address?